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Quantitative Aptitude Set -208

Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.

The questions below are based on the given Series-I. The series-I satisfy a certain pattern, follow the same pattern in Series-II and answer the questions given below.

1)

I. 8, 4, 6, 15, 52.5

II) 12 …. 78.75. If 78.75 is the nthterm find the value of n

A.6

B.4

C.5

D.7

E.8

2) I) 19, 38, 114, 570, 3990

II) 23 ….. 690. If 690 is the nthterm find the value of n

A.6

B.5

C.7

D.8

E.4

3) I) 15, 32, 68, 144, 304

II) 0.5 ….. 176. If 176 is the nthterm find the value of n

A.9

B.8

C.7

D.6

E.11

4) I) 11, 23, 33, 41, 47

II) 114 …… 154. If 154 is the nthterm find the value of n

A.6

B.3

C.5

D.7

E.4

5) I) 102, 342, 462, 542, 602

II) 7 ….. 447. If 447 is the nthterm find the value of n

A.2

B.3

C.4

D.6

E.5

Answers :

1) Answer: C

Series – I,

8 is the 1st term

8 * 0.5 = 4

4 * 1.5 = 6

6 * 2.5 = 15

15 * 3.5 = 52.5

Series – II,

12 is the 1st term

12 * 0.5 = 6

6 * 1.5 = 9

9 * 2.5 = 22.5

22.5 * 3.5 = 78.75 = 5th term

2) Answer: E

Series –I,

19 is the 1st term

19 * 2 = 38

38 * 3 = 114

114 * 5 = 570

570 * 7 = 3990

Series –II

23 is the 1st term

23 * 2 = 46

46 * 3 = 138

138 * 5 = 690 (4th term)

3) Answer: D

Series –I

15 is the 1st term

15 * 2 + 2 = 32

32 * 2 + 4 = 68

68 * 2 + 8 = 144

144 * 2 + 16 = 304(5th term)

Series – II,

0.5 is the 1st term

0.5 * 2 + 2 = 3

3 * 2 + 4 = 10

10 * 2 + 8 = 28

28 * 2 + 16 = 72

72 * 2 + 32 = 176 = 6th term

4) Answer: A

Series – I,

11 is the 1st term

11 + 12 = 23

23 + 10 = 33

33 + 8 = 41

41 + 6 = 47 (5th term)

Series – II,

114 is the 1st term

114 + 12 = 126

126 + 10 = 136

136 + 8 = 144

144 + 6 = 150

150 + 4 = 154 (6th term)

5) Answer: C

Series – I

102 is the 1st term

102 + 240/1 = 342

342 + 240/2 = 462

462 + 240/3 = 542

542 + 240/4 = 602

Series – II,

7 is the 1st term

7 + 240 = 247

247 + 240/2 = 367

367 + 240/3 = 447 (4th term)