A.Rs.1200

B.Rs.1100

C.Rs.1000

D.Rs.1300

E.None of these

2) A certain sum of money lent out at simple interest, amounts to Rs. 19500 in 3 years and Rs. 22500 in 5 years. Find the rate of interest per annum?

A.10 %

B.12 %

C.8 %

D.14 %

E.None of these

3) Sam invests Rs.7000 at the compound interest scheme at x% per annum for 6 years and Rahul invests same amount on same scheme at the same rate of interest for three years. If the end of the scheme ratio of the amount received by Sam to Rahul is 27:8, find the rate of interest per annum?

A.20%

B.30%

C.40%

D.50%

E.None of these

4) Rajesh deposited a certain amount to bank at simple interest rate of 10% per annum in the first year and it increased by 2% per annum every year. If he got Rs.9000 as interest at the end of three years, what is the deposited amount?

A.Rs.20000

B.Rs.25000

C.Rs.28000

D.Rs.18000

E.None of these

5) The sum Rs.16000 invested equally at two different rates of interest and the difference between the simple interest is Rs.1200 for 3 years. Find the difference between the rates of interest?

A.10%

B.5%

C.8%

D.12%

E.None of these

Answers :

1) Answer: E

Difference = P * r * r/(100 * 100)

36 = P * 20 * 20/(100 * 100)

P = 900

2) Answer: A

In 5 years, amount = 22500

In 3 years, amount = 19500

S.I for 2 years = 22500 – 19500 = 3000

S.I for 1 year = 3000/2 = Rs. 1500

S.I for 3 year = 1500*3 = Rs. 4500

Principle = 19500 – 4500 = Rs. 15000

According to the question,

(15000 * 3 * r) / 100 = 4500

r = (4500 * 100) / (15000 * 3) = 10 %

3) Answer: D

CI = P * (1 + R/100)ⁿ – P

Sam received the amount = 7000 * (1 + x/100)⁶

Rahul received the amount = 7000 * (1 + x/100)³

[7000 * (1 + x/100)⁶]/ [7000 * (1 + x/100)³]= 27/8

(1 + x/100)³ = 27/8

1 + x/100 = 3/2

100 + x = 150

x = 50%

4) Answer: B

P*1*10/100+P*1*12/100+P*14*1/100=9000

10P+12P+14P=900000

P=Rs.25000

5) Answer: B

8000*R1*3/100-8000*R2*3/100=1200

80*3(R1-R2) =1200

R1-R2=5%