A.25

B.20

C.35

D.30

E.None of these

2) Raghav spent 20% of his monthly income on household, 10% of the rest on education, 25% of the rest on entertainment and 20% of the rest on other expenditures. He saves Rs.____________. Amount spent by Raghav on entertainment is Rs._____________.

Which of the following option/options satisfy the given condition?

A.10800, 4500

B.13500, 5625

C.18900, 7875

D.All of the above

E.None of the above

3) The bag contains a certain number of red, yellow, orange and blue balls. The number of red balls is equal to 120% of the number of blue balls and the number of yellow balls is 50% of the number of red balls. If 40% of the orange balls is equal to the 60% of the blue balls and difference between the number of orange and red balls is 15, the find the total number of balls.

A.200

B.210

C.215

D.220

E.None of these

4) Total number of Red and Blue balls in a box is 100. If certain number of red and blue balls added to the box, then the number of red balls is increased by 20% and the number of blue balls increased by 9 and then total number of balls in the box is increased by 23%. What is the ratio of the initial number of red to blue balls in the box?

A.17: 3

B.3: 2

C.13: 12

D.3: 1

E.None of these

5) Rajeev scored 412 marks in an exam and Sanjay got 75 % marks in the same exam which is 8 marks more than Rajeev. If the minimum passing marks in the exam is 35 %, then how much more marks did Rajeev score than the minimum passing marks?

A.185

B.172

C.216

D.198

E.223

Answers :

1) Answer: D

According to the question,

(15 % – 10 %) of salary = 4000

5 % of salary = 4000

Total salary = 4000*(100/5) = Rs. 80000 = 100 %

Savings % = (20000/80000)*100 = 25 %

Total salary (100 %) = Expense (75 %) + Savings (25 %)

75 % = (15 % + 20 % + 10 % + X %)

X % = 75 % – 45 % = 30 %

2) Answer: D

Let, total income of Raghav be Rs. P

(a)

(100 – 20)/100 x (100 – 10)/100 x (100 – 25)/100 x (100 – 20)/100 x P = 10800

=> 80/100 x 90/100 x 75/100 x 80/100 x P = 10800

=> P = 10800 x 100/80 x 100/90 x 100/75 x 100/80

=> P = Rs.25000

Amount spent by Raghav on entertainment

= 80/100 x 90/100 x 25/100 x 25000

= Rs.4500 = 4500

=> Satisfies the given condition.

(b)

(100 – 20)/100 x (100 – 10)/100 x (100 – 25)/100 x (100 – 20)/100 x P = 13500

=> 80/100 x 90/100 x 75/100 x 80/100 x P = 13500

=> P = 13500 x 100/80 x 100/90 x 100/75 x 100/80

=> P = Rs.31250

Amount spent by Raghav on entertainment

= 80/100 x 90/100 x 25/100 x 31250

= Rs.5625 = 5625

=> Satisfies the given condition.

(c)

(100 – 20)/100 x (100 – 10)/100 x (100 – 25)/100 x (100 – 20)/100 x P = 18900

=> 80/100 x 90/100 x 75/100 x 80/100 x P = 18900

=> P = 18900 x 100/80 x 100/90 x 100/75 x 100/80

=> P = Rs.43750

Amount spent by Raghav on entertainment

= 80/100 x 90/100 x 25/100 x 43750

= Rs.7875 = 7875

=> Satisfies the given condition

3) Answer: C

Let Blue balls = x

Red balls = x * 120/100 = 6x/5

x* 60/100 = 40/100 *Orange balls

Orange balls = 3x/2

Yellow balls = 3x/5

3x/2 – 6x/5 = 15

15x – 12x = 150

x = 50

Total number of balls = x + 6x/5 + 3x/2 + 3x/5

= 50+60+75+30

= 215

4) Answer: E

Number of red balls = x

Number of blue balls = 100 – x

x * 120/100 + (100 – x + 9) = 100 * 123/100

6x/5 + 109 – x = 123

6x + 545 – 5x = 123 * 5

x = 70

Number of blue balls = 100 – 70 = 30

Required ratio = 7: 3

5) Answer: C

Let x be the total mark in that exam, then

Rajeev’s score = 412 marks, Sanjay’s score = 75 % = Rajeev’s score + 8

Sanjay = 412 + 8 = 420 = 75 % of total marks

(75/100)* x = 420

x = 420 * (100/75) = 560

Minimum passing marks = 35 % of total marks

= > (35/100)* 560 = 196

Rajeev scored 216 marks more than the passing marks.