Quantitative Aptitude Set -361
Sep 27 2024
Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.
Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give an answer as,
1)
II)y2– 14y + 48 = 0
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
2) I) x2 + 20x + 99 = 0
II)y2– 12y – 189 = 0
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
3) I) 2x2 – 15x + 18 = 0
II)3y2– 11y + 10 = 0
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
4) I) x2 – 17x + 42 =0
II)y2– 19y + 70 = 0
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
5) I) x2 + 31x + 184 = 0
II)y2+ 15y + 56 = 0
A.x > y
B.x ≥ y
C.x = y or relationship can’t be determined.
D.x < y
E.x ≤ y
Answers :
1) Answer: B
x2 - 23x + 120 = 0
x2 – 15x – 8x + 120 = 0
x(x – 15) – 8(x – 15) = 0
(x – 8)(x – 15) = 0
x = 8, 15
y2 – 14y + 48 = 0
y2 – 8y – 6y + 48 = 0
y(y – 8) – 6(y – 8) = 0
(y – 6)(y – 8) = 0
y = 6, 8
x ≥ y
2) Answer: E
x2 + 20x + 99 = 0
x2 + 11x + 9x + 99 = 0
x(x + 11) + 9(x + 11) = 0
(x + 9)(x + 11) = 0
x = -9, -11
y2 – 12y – 189 = 0
y2 – 21y + 9x – 189 = 0
y(y – 21) + 9(x – 21) = 0
(y + 9)(y – 21) = 0
y = -9, 21
x ≤ y
3) Answer: C
2x2 – 15x + 18 = 0
2x2 – 12x – 3x + 18 = 0
2x(x – 6) – 3(x – 6) = 0
(2x – 3)(x – 6) = 0
x = 3/2, 6
3y2 – 11y + 10 = 0
3y2 – 6y – 5y + 10 = 0
3y(y – 2) – 5(y – 2) = 0
(3y – 5)(y – 2) = 0
y = 2, 5/3
Relationship between x and y cannot be established.
4) Answer: C
x2 – 17x + 42 =0
x2 – 14x – 3x + 42 = 0
x(x – 14) – 3(x – 14) = 0
(x – 3)(x – 14) = 0
x = 3, 14
y2 – 19y + 70 = 0
y2 – 14y – 5y + 70 = 0
y(y – 14) – 5(y – 14) = 0
(y – 5)(y – 14) = 0
y = 5, 14
Relationship between x and y cannot be established.
5) Answer: E
x2 + 31x + 184 = 0
x2 + 23x + 8x + 184 = 0
x(x + 23) + 8(x + 23) = 0
(x + 8)(x + 23) = 0
x = -8, -23
y2 + 15y + 56 = 0
y2 + 8y + 7y + 56 = 0
y(y + 8) + 7(y + 8) = 0
(y + 7)(y + 8) = 0
y = -7, -8
x ≤ y
