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Quantitative Aptitude Set -390

Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.

1) Average weight of five persons is 51 kg and each of them in different weights. If the average weight of heaviest and lightest persons is 52 kg and the average

weight of second heaviest and fourth heaviest persons is 48 kg, then find the weight of the third lightest person?

A.63 kg

B.48 kg

C.32 kg

D.55 kg

E.None of these

2) Average weight of A, B and C is 44 kg. If the average weight of A, B and C is 10% more than the average weight of A, B, C, D and E, then find the weight of D and E together?

A.68 kg

B.48 kg

C.56 kg

D.72 kg

E.None of these

3) Ratio of the height of A and B is 9:7 and the height of C is 66.67% of the height of A. If the difference between the height of B and C is 21 cm, then find the average height of A and B together?

A.136 cm

B.124 cm

C.145 cm

D.168 cm

E.None of these

4) If the weight of A is 8 kg more than that of B and the weight of C is 12 kg more than that of D and the weight of D is 12 kg more than that of B. If the weight of D is 60 kg, then find the average weight of B, C and D together?

A.72 kg

B.56 kg

C.60 kg

D.48 kg

E.None of these

5) The weight of A is 28.56% less than that of B and the weight of C is 25% more than that of B. If the average weight of A, B and C is 83 kg, then find the average weight of A and B together?

A.63 kg

B.84 kg

C.45 kg

D.72 kg

E.None of these

Answers :

1) Answer: D

Weight of third lightest person=x

51*5=52*2+48*2+x

255-200=x

x=55 kg

2) Answer: A

The average weight of A, B and C=44 kg

The average weight of A, B, C, D and E=44*100/110=40 kg

The weight of D and E=40*5-44*3=68 kg

3) Answer: D

A = 9x

B = 7x

C = 9x *2/3 = 6x

7x - 6x = 21

x= 21 cm

A = 9 * 21 = 189 cm

B = 7 * 21 = 147 cm

Required average=(189 + 147)/2 = 336/2 = 168 cm

4) Answer: C

D = 60 kg

B = 60-12 = 48 kg

A = 48 + 8 = 56 kg

C = 60 + 12 = 72 kg

Required average=(60 + 48 + 72)/3 = 180/3 = 60 kg

5) Answer: D

Let the weight of B=14x kg

The weight of A=14x*5/7=10x kg

The weight of C=14x*125/100=17.5x kg

14x+10x+17.5x=83*3

41.5x=249

x=6

The weight of A=10*6=60 kg

The weight of B=14*6=84 kg

Required average=(60+84)/2=72 kg

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