Quantitative Aptitude Set -392
Oct 28 2024
Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.
1) If the length of the rectangle is increased by 20% and the breadth of the rectangle is decreased by 15%, then find the percentage increase or decrease of
A.1% decrease
B.2% increase
C.5% decrease
D.4% increase
E.None of these
2) Circumference of the circle is 88 cm. If the radius of the circle is seven-fifth of side of the square whose perimeter is 10 cm more than the perimeter of the equilateral triangle. What is the area of the equilateral triangle?
A.25√3 cm2
B.26√3 cm2
C.27√3 cm2
D.28√3 cm2
E.None of these
3) The perimeter of a square is 84 cm. Find the volume of sphere, if the radius of the sphere is equal to the side of the square?
A.36524 cm3
B.36756 cm3
C.38808 cm3
D.41562 cm3
E.None of these
4) If the ratio of the side of the cube to side of the square is 1:2 and the ratio of the length to breadth of the rectangle is 5:4 and the area of the rectangle is 80cm2. If the perimeter of the rectangle is equal to the area of the square, then find the volume of the cube?
A.64 cm3
B.8 cm3
C.25 cm3
D.27 cm3
E.None of these
5) The ratio of Curved Surface Area to Total Surface Area of Cylinder is 3: 7. If the Curved Surface Area of the Cylinder is 3696 m², find the height of the cylinder.
A.23m
B.21m
C.27m
D.29m
E.None of these
Answers :
1) Answer: B
Let initial Area of the rectangle = 100
100 * 120/100 * 85/100 = 102
Area = 2% increase
2) Answer: A
Circumference of the circle = 2 * 22/7 * r
88 = 2 * 22/7 * r
Radius of the circle = 14 cm
14 = 7/5 * a
a = 10cm
Perimeter of the square = 4 * 10 = 40 cm
Perimeter of the equilateral triangle = 40 – 10 = 30 cm
Side of the equilateral triangle = 3 * a = 30
Side of the equilateral triangle = 10 cm
Area of the equilateral triangle = √3/4 * 10 * 10
= 25√3 cm2
3) Answer: C
The perimeter of a square = 84 cm
4a = 84
Side (a) = 21 cm = Radius of the sphere
Volume of sphere = (4/3) * πr3
= > (4/3) * (22/7) * 21 * 21 * 21
= > 38808 cm3
4) Answer: D
5x*4x=80
x=2
Now, perimeter of the rectangle=2(9*2)=36cm
Thus, side of the square=6cm
And, side of the cube=3cm
Hence, volume of the cube=3*3*3=27cm3
5) Answer: B
Curved Surface Area of Cylinder = 2πrh
Total Surface Area of Cylinder = 2πr (h + r)
According to question,
2πrh/(2πr (h + r)) = 3/7
h/(h + r) = 3/7
7h = 3h + 3r
4h = 3r
r = 4h/3
And, Curved Surface Area of Cylinder = 3696m²
2πrh = 3696
2π × 4h/3 × h = 3696
h² = 21× 21
h = 21 m.
