Quantitative Aptitude Set -401
Nov 06 2024
Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.
Study the following information carefully and answer the given questions.
A company manufactures three types of product
35% of the total products are product B. Ratio of plastic and metallic products in product B is 4:3. Number of Plastic materials of product A is 10% more than the number of plastic materials of product B. Ratio of metallic materials of product C and the number of plastic materials of product A is 3 :5 respectively. Number of Metallic materials of product A is 20% less than the number of metallic materials of product B.
1) Find the difference between the number of plastic materials and the number of metallic materials of product C.
A.694
B.784
C.796
D.736
E.682
2) Find the respective ratio of the number of metallic materials of product A to the number of metallic materials of product B.
A.1:2
B.3:2
C.4:5
D.2:5
E.5:4
3) Find the total number of product A and product B.
A.11000
B.11020
C.11080
D.11010
E.11040
4) Number of plastic materials of product A is approximately what percentage of total number of materials of product B?
A.63 %
B.72 %
C.56 %
D.44 %
E.85 %
5) Find the difference between the number of Plastic materials of product B and the number of metallic materials of product A?
A.1400
B.1380
C.1320
D.1200
E.1280
Explanation :
Total = 16000
35% of the total products are product B
Total products of B type = 35% 16000 = 5600
Ratio of plastic and metallic products in product B is 4:3
Plastic products of product B = 4/7 * 5600 = 3200
Metallic products of product B = 3/7 * 5600 = 2400
Plastic products of product A = 110% (number of plastic products of product B)
= > 110 % 3200 = 3520
Ratio of metallic products of product C and the number of plastic product of product A is 3:5 respectively
Metallic products of product C = 3/5 * 3520 = 2112
Number of Metallic products of product A = 80% of 2400 =1920
Total products of B = 5600
Total products of A = 3520 + 1920 = 5440
Total Products of C = 16000 – (5600 + 5440) = 4960
Total Plastic products of Product C = 4960 – 2112 = 2848

1) Answer: D
Difference between the number of plastic materials and the number of metallic materials of product C
= 2848 – 2112
=736
2) Answer: C
Required Ratio = 1920: 2400 = 4:5
3) Answer: E
Total = 5440 + 5600 = 11040
4) Answer: A
Number of plastic materials of product A = 3520
Total product of B = 5600
Required percentage = (3520 / 5600) * 100= 62.85 % ≈ 63%
5) Answer: E
Difference = 3200 – 1920= 1280
