Quantitative Aptitude Set -416
Nov 21 2024
Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.
Study the following information carefully and answer the given questions.
The following pie chart shows the total number of students in 6 different schools and the table shows
1) Find the difference between the total number of boys in School P to that of total number of girls in School R?
A) 1368
B) 1892
C) 1456
D) 1575
E) None of these
2) Find the average number of girls in School P, Q and S together?
A) 5040
B) 5180
C) 4890
D) 4560
E) None of these
3) Find the ratio between the total number of students in School R to that of total number of boys in School T?
A) 8: 7
B) 15: 14
C) 23: 21
D) 32: 29
E) None of these
4) The total number of girls in School U is approximately what percentage of total number of boys in School Q?
A) 110 %
B) 95 %
C) 135 %
D) 70 %
E) 120 %
5) Find the central angle for School T?
A) 720
B) 800
C) 660
D) 840
E) None of these
Answers :
1) Answer: A
The total number of boys in School P
= > 60000*(15/100)*(52/100) = 4680
The total number of girls in School R
= > 60000*(12/100)*(46/100) = 3312
Required difference = 4680 – 3312 = 1368
2) Answer: A
The total number of girls in School P, Q and S together
= > 60000*(15/100)*(48/100) + 60000*(18/100)*(52/100) + 60000*(16/100)*(54/100)
= > 4320 + 5616 + 5184 = 15120
Required average = 15120/3 = 5040
3) Answer: B
The total number of students in School R
= > 60000*(12/100) = 7200
The total number of boys in School T
= > 60000*(20/100)*(56/100) = 6720
Required ratio = 7200: 6720 = 15: 14
4) Answer: A
The total number of girls in School U
= > 60000*(19/100)*(50/100) = 5700
The total number of boys in School Q
= > 60000*(18/100)*(48/100) = 5184
Required % = (5700/5184)*100 = 110 %
5) Answer: A
The central angle for School T
= > (20/100)*360 = 720
