Quantitative Aptitude Set -418
Nov 23 2024
Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.
In each of the following questions, two equations are given. You have to solve these equations to find the relation between x and y.
1)
I)
II) 2y2– 15y + 28 = 0
A.x < y
B.x > y
C.x ≤ y
D.x ≥ y
E.Relationship between x and y cannot be determined
2)
I) 2x2– 7x + 6 = 0
II) y2+ 13y + 42 = 0
A.x < y
B.x > y
C.x ≤ y
D.x ≥ y
E.Relationship between x and y cannot be determined
3)
I) 2x2– 9x + 9 = 0
II) 8y2+ 34y + 21 = 0
A.x < y
B.x > y
C.x ≤ y
D.x ≥ y
E.Relationship between x and y cannot be determined
4)
I) 2x2– 13x + 15 = 0
II) 3y2+ 28y + 65 = 0
A.x < y
B.x > y
C.x ≤ y
D.x ≥ y
E.Relationship between x and y cannot be determined
5)
I) x2= 2401
II) y3= 117649
A.x < y
B.x > y
C.x ≤ y
D.x ≥ y
E.Relationship between x and y cannot be determined
Answers :
1) Answer: A
I) 8x2– 15x + 7 = 0
=> 8x2 – 8x – 7x + 7 = 0
=> 8x(x – 1) – 7(x – 1) = 0
=> (8x – 7)(x – 1) = 0
=> x = 7/8, 1
II) 2y2– 15y + 28 = 0
=> 2y2 – 8y – 7y + 28 = 0
=> 2y(y – 4) – 7(y – 4) = 0
=> (2y – 7)(y – 4) = 0
=> y = 7/2, 4
Hence, x < y
2) Answer: B
I) 2x2– 7x + 6 = 0
=> 2x2 – 4x – 3x + 6 = 0
=> 2x(x – 2) – 3(x – 2) = 0
=> (2x – 3)(x – 2) = 0
=> x = 3/2, 2
II) y2+ 13y + 42 = 0
=> y2 + 6y + 7y + 42 = 0
=>y(y + 6) + 7(y + 6) = 0
=> (y + 7)(y + 6) = 0
=> y = -7, -6
Hence, x > y
3) Answer: B
I) 2x2– 9x + 9 = 0
=> 2x2 – 6x – 3x + 9 = 0
=> 2x(x – 3) – 3(x – 3) = 0
=> (2x – 3)(x – 3) = 0
=> x = 3/2, 3
II) 8y2+ 34y + 21 = 0
=> 8y2 + 28y + 6y + 21 = 0
=> 4y(2y + 7) + 3(2y + 7) = 0
=> (4y + 3)(2y + 7) = 0
=> y = -3/4, -7/2
Hence, x > y
4) Answer: B
I) 2x2– 13x + 15 = 0
=> 2x2 – 10x – 3x + 15 = 0
=> 2x(x – 5) – 3(x – 5) = 0
=> (2x – 3)(x – 5) = 0
=> x = 3/2, 5
II) 3y2 + 28y + 65 = 0
=> 3y2 + 15y + 13y + 65 = 0
=> 3y(y + 5) + 13(y + 5) = 0
=> (3y + 13)(y + 5) = 0
=> y = -13/3, -5
Hence, x > y
5) Answer: C
I) x2= 2401
=> x = ± √2401
=> x = ± 49
II) y3= 117649
=> y = 3√117649
=> y = 49
Hence, x ≤ y
