Quantitative Aptitude Set -458
Jan 02 2025
Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.
In the following questions, two equations I and II are given. You have to solve both equations and give an answer as,
1) I) x2 + 16x +
II)y2 + 24y + 143=0
a) x > y
b) x ≥ y
c) x < y
d) x ≤ y
e) x = y or the relation cannot be established.
2) I) 2x2 – 30x + 88 = 0
II)3y2– 30y + 48 = 0
a) x > y
b) x ≥ y
c) x < y
d) x ≤ y
e) x = y or the relation cannot be established.
3) I) x2 + 23x + 120 = 0
II) y2+ 26y + 165 = 0
a) x > y
b) x ≥ y
c) x < y
d) x ≤ y
e) x = y or the relation cannot be established.
4) I) 2x2 + 26x + 72 = 0
II) y2+ 13y + 36 = 0
a) x > y
b) x ≥ y
c) x < y
d) x ≤ y
e) x = y or the relation cannot be established.
5) I) x2 – 4x – 221 = 0
II) y2– 26y + 153 = 0
a) x > y
b) x ≥ y
c) x < y
d) x ≤ y
e) x = y or the relation cannot be established.
Answers :
1) Answer: A
x2 + 16x + 63=0
x2 + 9x + 7x + 63=0
x(x + 9) + 7(x + 9)=0
(x + 7) (x + 9)=0
x=-7, -9
y2 + 24y + 143=0
y2 + 11y + 13y + 143=0
y(y + 11) + 13(y + 11)=0
(y + 13)(y + 11)=0
y=-13, -11
Hence x > y
2) Answer: E
2x2 – 30x + 88=0
2x2 – 22x – 8x + 88=0
2x(x – 11) – 8(x – 11)=0
(2x – 8) (x – 11)=0
x=4, 11
3y2 – 30y + 48=0
3y2 – 24y – 6y + 48=0
3y(y – 8) – 6(y – 8)=0
(3y – 6) (y – 8)=0
y=2, 8
Hence Relationship between x and y cannot be established.
3) Answer: E
x2 + 23x + 120=0
x2 + 15x + 8x + 120=0
x(x + 15) + 8(x + 15)
(x + 8)(x + 15)=0
x = -8, -15
y2 + 26y + 165=0
y2 + 15y + 11y + 165=0
y(y + 15) + 11 (y + 15)=0
(y + 11) (y + 15)=0
y=-11, -15
Hence the relationship cannot be established.
4) Answer: E
2x2 + 26x + 72=0
2x2 + 18x + 8x + 72=0
2x(x + 9) + 8(x + 9)=0
(2x + 8) (x + 9)=0
x=-4, -9
y2 + 13y + 36=0
y2 + 9y + 4y + 36=0
y(y + 9) + 4 (y + 9)=0
(y + 4)( y + 9)=0
y=-4, -9
Hence the relationship cannot be established.
5) Answer: E
x2 – 4x – 221=0
x2 – 17x + 13x – 221=0
x(x – 17) + 13 (x – 17)=0
(x + 13)(x – 17)=0
x=-13, 17
y2 – 26y + 153=0
y2 – 17y – 9y + 153=0
y(y – 17) – 9(y – 17)=0
(y – 9)(y – 17)=0
y=9, 17
Hence Relationship cannot be established between x and y.
