
Quantitative Aptitude Set -477
Jan 21 2025
Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.
1) A train crosses a 400 m long platform in 42 seconds and also crosses a man running in opposite direction at the speed of 20 kmph in 13.5 seconds. What is the
A.40 kmph
B.50 kmph
C.60 kmph
D.80 kmph
E.None of these
2) The ratio of the length of train A to B is 4: 5 and the speed of the train A to B is 3: 4. If train A crosses Train B running in same direction in 81 seconds and train A also crosses a pole in 12 seconds, then find the speed of train B?
A.50 kmph
B.60 kmph
C.80 kmph
D.Cannot be determined
E.None of these
3) Train A crosses a platform of length 300 m in 24 seconds but the same train crosses a man in 8 seconds. Find the length of train?
A.250 m
B.300 m
C.150 m
D.200 m
E.None of these
4) A train crosses 300 m long tunnel in 36 seconds and the same train crosses a pole in 18 seconds. What is the length of the train?
A.200 m
B.300 m
C.250 m
D.Cannot be determined
E.None of these
5) Train A crosses Train B running in opposite direction at the speed of 60 kmph in 6 seconds and crosses a pole in 8 seconds. If the length of the train B is 100 m longer than that of train A, the find the length of train A?
A.200 m
B.400 m
C.300 m
D.Cannot be determined
E.None of these
Answers :
1) Answer: C
Length of the train = x
Speed of train = y
x + 400 = y * 5/18 * 42
3x + 1200 = 35y
x = (y + 20) * 5/18 * 13.5
2x = 7.5y + 150
2 * ((35y – 1200)/3) = 7.5y + 150
70y – 2400 = 22.5y + 450
47.5y = 2850
y = 60 km/hr
2) Answer: D
Length of train A = 4x
Length of train B = 5x
Speed of train A = 3y
Speed of train B = 4y
9x = (4y – 3y) * 5/18 * 81
2x = y * 5
4x = 3y * 5/18 * 12
4x = 10y
2x = 5y
We cannot find the answer.
3) Answer: C
The speed is equal. So,
(T.L + 300) / 24 = T.L / 8
T.L + 300 = 3T.L
2T.L = 300
T.L = 150
The length of train = 150 m
4) Answer: B
Distance = Speed * Time
Length of the train = x
Speed of train = y
x + 300 = y * 5/18 * 36
x + 300 = 10y
x = y * 5/18 * 18
x = 5y
x + 300 = 2x
x = 300 m
5) Answer: D
Length of train A = x
Length of train B = x + 100
Speed of train A = y
2x + 100 = (y + 60) * 5/18 * 6
6x + 300 = 5y + 300
6x = 5y
x = y * 5/18 * 8
We cannot be find the answer.