Quantitative Aptitude Set -571
Apr 25 2025
Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.
1) Anju deposited Rs.24000 in a bank offering 15% Compound interest for 3 years compounded annually. What is the total interest received by Anju?
B.Rs.14850
C.Rs.16251
D.Rs.17851
E.None of these
2) Mr.Anish invested Rs.52000 in two different schemes which offers SI at different rate of interest 13% and 8% respectively. If at the end of 2 years he earned overall interest is Rs.11920, then find the sum which is invested at 8% rate of interest?
A.Rs.32000
B.Rs.16000
C.Rs.20000
D.Rs.36000
E.Can’t be determined
3) The difference between the compound interest and simple interest for the sum of Rs.25000 at the end of two years at the rate of 20% per annum?
A.Rs.1200
B.Rs.1400
C.Rs.1500
D.Rs.1600
E.None of these
4) Arun invested Rs.5000 in a bank at Simple interest for 2 years and receives an interest of Rs.500. What is the rate of interest?
A.3%
B.5%
C.7%
D.9%
E.None of these
5) If Rs.11750.4 amount is received for lending Rs.x for 3 years at 20% per annum compound interest, find the value of x?
A.Rs.6500
B.Rs.6800
C.Rs.7200
D.Rs.7800
E.Rs.7500
Answers :
1) Answer: A
Interest received by Anju = 24000 * ((1 + 0.15)3 – 1)
= Rs.12501
2) Answer: B
Let amount invested in 1st scheme be x,
Amount invested in 2nd scheme be 52000-x
It is given that,
x=Rs.36000
Therefore amount invested in 2nd scheme = 52000-36000 = Rs.16000
3) Answer: E
Difference = (25000 * 20 * 20)/(100 * 100)
= Rs.1000
4) Answer: B
Given that, SI = Rs.500, n = 2 years and P = Rs.5000
SI = Pnr/100
r = (100 * SI)/(P * n)
= (100 * 500)/(5000 * 2)
= 5%
5) Answer: B
CA = P * (1 + r/100)n
11750.4 = x * (1 + 20/100)3
x = 6800
