Quantitative Aptitude Set -590
May 14 2025
Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.
1) A train crosses a 420 m long platform in 36 seconds at the speed of 90 kmph. If the speed of the train is decreased by 16.67%, then find the time taken by train
A.9.6 seconds
B.12 seconds
C.10 seconds
D.16.5 seconds
E.None of these
2) A train crosses a car is running in the opposite direction at the speed of 24 kmph in 18 seconds. If the speed of train is double that of car, then find the time taken by the train to cross 140 m long platform?
A.37.5 seconds
B.25 seconds
C.30 seconds
D.28.8 seconds
E.14.4 seconds
3) Train A crosses train B is running in the same direction in 108 seconds and also train A crosses a tower in 21.6 seconds. If the speed of train B is 33(1/3)% more than the speed of train A, then find the time taken by train B crosses a pole?
A.14.4 seconds
B.12 seconds
C.18 seconds
D.10.8 seconds
E.Cannot be determined
4) Ratio of the speed of trains A and B is 4:5. Train A is 160 m long and train B is 240 m long and train B travels at the speed of 50 kmph. If the two trains A and B are running in opposite direction, then find the time taken by both trains to cross each other?
A.16 seconds
B.21 seconds
C.12 seconds
D.27 seconds
E.None of these
5) Train A crosses a standing man in 24 seconds and also crosses train B running in the opposite direction at the speed of 54 kmph in 21.6 seconds. If the ratio of the length of trains A and B is 4:5 respectively, then find the speed of train A?
A.27 kmph
B.54 kmph
C.45 kmph
D.36 kmph
E.None of these
Answers :
1) Answer: A
Length of the train=x
(x+420)=90*5/18*36
x=480 m
Speed of the train is decreased by 16.67%=90*5/6=75 m/s
Required time=(480+240)/75=720/75=9.6 seconds
2) Answer: A
Length of train = (24 + 24 * 2) * 5/18 * 18
= 360 m
Required time = (360 + 140)/(24 * 2) * 5/18
= 37.5 seconds
3) Answer: D
Speed of train A = 3x
Speed of train B = 400/300 * 3x = 4x
Length of train A = y
Length of train B = z
y = 3x * 5/18 * 21.6
y = 18x
y + z = (4x – 3x) * 5/18 * 108
y + z = 30x
z = 30x – 18x = 12x
Required time = 12x/4x * 5/18 = 10.8 seconds
4) Answer: A
Speed of train A=50*4/5=40 kmph
Relative speed=40+50=90 kmph
Time taken by both trains A and B to cross each other=x
160+240=90*5/18*x
400*18/5*1/90=x
x=16 seconds
5) Answer: D
Length of train A=4x
Length of train B=5x
Let speed of train A =y
4x=y*5/18*24
3x=5y
4x+5x=(y+54)*5/18*21.6
3x=(2y+54*2)
3x=2y+108
y=36 kmph
