A.Rs.2640

B.Rs.2680

C.Rs.2720

D.Rs.2760

E.Rs.2790

2) A man invested Rs. 2500 in SI at R% p.a in scheme A for 8 years and the same man invested Rs. 1200 in SI at (R+2)%p.a in scheme B for 5 years. If the total interest received by the man is Rs. 900, then what is the value of R%?

A.5%

B.1%

C.4%

D.3%

E.2%

3) Kavin borrowed Rs.X at 20% per annum on compound interest and the same amount he lent to his friend at 40% per annum on simple interest. If the extra interest earned is Rs.900 at the end of 2 years, then find the value of X?

A.2500

B.4500

C.3000

D.3500

E.None of these

4) Ram invested Rs.x in simple interest at the rate of 12% per annum for 5 years and Sam invested Rs.(x + 1000) in compound interest at the rate of 10% per annum for two years. If Ram received the interest amount is Rs.1350 more than that of Sam, then find the value of x.

A.4000

B.3000

C.5000

D.6000

E.None of these

5) Sathya invested Rs.x in simple interest scheme A at 15% per annum and also she invested Rs.(5000 – x) in compound interest scheme B at 20% per annum. After 2 years, Sathya received the interest from scheme A and B is Rs.1920. Find the value of x?

A.2000

B.2400

C.2800

D.3200

E.None of these

Answers :

1) Answer: A

6930 – x = x * 18 * 3/100

1.54x =6930

x = 4500

CI received by Soni = (4500 + 1500) * (1 + 20/100)² – (4500 + 1500)

= Rs.2640

2) Answer: D

Total interest received,

= (2500 x R x 8)/100 +(1200 x (R + 2) x 5)/100 = (200R+60R+120)

ATQ,

260R + 120 = 900

260R = 900 – 120

R = 3%

3) Answer: A

Let the amount borrowed=X

(X*40*2/100)-(X*120/100*120/100-X)=900

0.8X-1.44X+X=900

0.36X=900

X=900/0.36=2500

4) Answer: A

SI = P * N * R/100

CI = P * (1 + R/100)ⁿ – P

SI = x * 12 * 5/100 = 0.6x

CI = (x + 1000) * (1 + 10/100)² – (x + 1000)

= 21/100 * (x + 1000)

0.6x – 21x/100 – 210 = 1350

60x – 21x – 21000 = 135000

x = Rs.4000

5) Answer: A

(x * 15 * 2/100) + ((5000 – x) * (120/100)² – (5000 – x)) = 1920

0.3x + 7200 – 1.44x – 5000 + x = 1920

0.14x = 280

x = 2000