
Quantitative Aptitude Set -624
Jun 17 2025
Here we are providing new series of Quantitative Aptitude Questions for upcoming exams, so the aspirants can practice it on a daily basis.
1) A milkman has the mixture of milk and water in the ratio of 5:3. If he sold 16 liters of the mixture and added 16 liters of the water to the mixture, so the ratio
A.48 liters
B.56 liters
C.64 liters
D.80 liters
E.None of these
2) A vessel has 180 litres of the mixture of petrol and kerosene in the ratio of 5:4. If x litres of the mixture is taken out and then added 40 litres of petrol and 26 litres of kerosene. If the final ratio of the petrol and kerosene is 4:3, then find the value of x?
A.27
B.30
C.36
D.45
E.None of these
3) A milkman has 90 litres of milk. 9 litres of milk sold by him and he added same amount of water to the milk. This process is repeated 2 more times. Find the quantity of water in the final mixture.
A.65.61 litres
B.64.59 litres
C.16.69 litres
D.24.39 litres
E.58.24 litres
4) Vessel A contains the mixture of milk and water in the ratio of 4:1 and the vessel B contains the mixture of milk and water in the ratio of 3:4. If both vessels mixtures are mixed, what is the ratio of the milk and water in the final mixture?
A.37:23
B.41:25
C.43:27
D.45:29
E.None of these
5) A milkman has 60 liters mixture of milk and water in the ratio of 3:2 and then he sold 20 liters of the mixture. Then the milk man added x liters of water, now the ratio of the water and milk becomes 7:6. Find the value of x?
A.10
B.12
C.14
D.15
E.None of these
Answers :
1) Answer: C
Milk in 16 liters = 5/8 * 16 = 10 liters
Water in 16 liters = 3/8 * 16 = 6 liters
(5x – 10) / (3x – 6 + 16) = 15/17
45x + 150 = 85x – 170
40x = 320
x = 8 liters
Total quantity of the mixture = 8 * 8 = 64 liters
2) Answer: C
Petrol in 180 litres = 5/9 * 180 = 100
Kerosene in 180 litres = 4/9 * 180 = 80
(100 – 5x/9 + 40)/(80 – 4x/9 + 26) = 4/3
(900 – 5x + 360) * 3 = 4 * (720 – 4x + 234)
3780 – 15x = 3816 – 16x
x = 36 litres
3) Answer: D
The amount of milk replaced is 10% of total mixture.
The milk in the final mixture = 90 * 90/100 * 90/100 * 90/100 = 65.61
The water in final mixture = 90 – 65.61 = 24.39litres
4) Answer: C
Milk in vessel A = 4/5
Water in vessel A = 1/5
Milk in vessel B = 3/7
Water in vessel A = 4/7
Required ratio = (4/5 + 3/7):(1/5 + 4/7)
=43:27
5) Answer: B
Milk in 60 liters = 3/5 * 60 = 36 liters
Water in 60 liters = 2/5 * 60 = 24 liters
Milk in 20 liters = 3/5 * 20 = 12 liters
Water in 20 liters = 2/5 * 20 = 8 liters
(36 – 12)/(24 – 8 + x) = 6/7
96 + 6x = 168
6x = 72
x = 12 liters